Output :: If limit=5, then, 5*1=5, 5*2=10 …………. ……….. ……….. 5*10=50

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{      clrscr();

       int result,i,n;

       printf("Enter number=");

       scanf("%d",&n);

       result=1;

       i=1;

       while(i<=10)

       {  result= n*i;

                  printf("\n\n %d*%d=%d",n,i,result);

                  i=i++;}

                  getch();  }